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Answer :
The drag force exerted by the water on a 950-kg motorboat that accelerates at 2.3 m/s² with a propeller thrust of 4.3 kN is 2115 N.
To find the drag force exerted by the water on the boat, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the thrust force provided by the propeller and the drag force by the water are the two main forces acting on the motorboat.
The motorboat has a mass of 950 kg and is accelerating at 2.3 m/s2. The propeller provides a thrust force of 4.3 kN, which is equivalent to 4300 N. According to Newton's second law, the net force acting on the boat can also be calculated as the product of its mass and acceleration (950 kg * 2.3 m/s2 = 2185 N).
The net force is the difference between the thrust force and the drag force since they are in opposite directions. Thus, the drag force can be calculated as follows:
Thrust Force - Drag Force = Net Force
4300 N - Drag Force = 2185 N
Drag Force = 4300 N - 2185 N
Drag Force = 2115 N.
Therefore, the drag force exerted by the water on the boat is 2115 N.
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