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Answer:
C. 64°
Step-by-step explanation:
[tex]{ \tt{ \cos( \theta) = \frac{adjacent}{hypotenuse} }} \\ \\ { \tt{ \cos( \theta) = \frac{7}{16} }} \\ \\ { \tt{ \theta = { \cos }^{ - 1} ( \frac{7}{16} )}} \\ \\ { \tt{ \theta = 64 \degree}}[/tex]
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Rewritten by : Barada
Answer: Choice C) 64 degrees
Work Shown:
[tex]\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(\theta) = \frac{7}{16}\\\\\cos(\theta) = 0.4375\\\\\theta = \cos^{-1}(0.4375)\\\\\theta \approx 64.0555^{\circ} \\\\\theta \approx 64^{\circ} \\\\[/tex]
Note: some calculators will use the notation arccos in place of the [tex]\cos^{-1}[/tex]
