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Suppose you start with 6.00 moles of [tex]N_2[/tex] and 6.00 moles of [tex]H_2[/tex] in a 4.00 L flask. What are the initial concentrations of [tex]N_2[/tex] and [tex]H_2[/tex]?

Answer :

To find initial concentrations, divide moles by volume: 6.00 moles of N2 and H2 each in a 4.00 L flask yields a concentration of 1.5 M for both N2 and H2.

To calculate the initial concentrations of N2 and H2 in a 4.00 L flask, you can use the formula for concentration, which is the number of moles of substance divided by the volume of the solution. For N2, the initial concentration would be 6.00 moles N2 / 4.00 L flask = 1.5 M (moles per liter). Similarly, the initial concentration of H2 would also be 6.00 moles H2 / 4.00 L flask = 1.5 M. Therefore, both N2 and H2 have the same initial concentration of 1.5 M in the flask.

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