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Morgan and Tina each have 6 cars. Morgan gave her brother [tex]\frac{3}{6}[/tex] of her cars, and Tina gave [tex]\frac{5}{6}[/tex] of her cars to her little brother. What fraction of their cars did Morgan and Tina each give away?

Answer :

Morgan gave away 3/6 of her 6 cars and Tina gave 5/6 of hers. Totaling 8 cars given away out of the 12 cars they had together, they gave away 2/3 of their cars after simplifying the fraction.

Understanding the Fraction of Cars Given Away by Morgan and Tina

Let's solve the problem step by step:

  • Morgan starts with 6 cars and gives away 3/6 of her cars, which is equivalent to 3 cars.
  • Tina also starts with 6 cars but gives away 5/6 of her cars, which means she gives away 5 cars.

To find the fraction of their toys that Morgan and Tina both gave away, we sum the number of cars each gave away and divide by the total number they started with:

Total cars given away by both = Morgan's 3 cars + Tina's 5 cars = 8 cars.

Total cars they started with = Morgan's 6 cars + Tina's 6 cars = 12 cars.

The fraction of cars they gave away is 8/12. However, this fraction can be simplified by dividing both the numerator and the denominator by 4.

So, the simplified fraction is 2/3, meaning Morgan and Tina together gave away two-thirds of their cars.

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