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A toy rocket is launched vertically upwards from the ground. During its movement, the rocket passes a 2 m high window, the bottom of which is 10 m above the ground. The rocket takes 0.2 seconds to pass the window.

a) At what speed was the rocket launched?
(Answer: 17.8 m/s)

b) What is the maximum height the rocket reaches?
(Answer: 16.1 m)

Answer :

Final answer:

The rocket was launched at a speed of 1.96 m/s and reaches a maximum height of 16.1 meters.

Explanation:

To calculate the speed at which the rocket was launched, we can use the fact that it takes 0.2 seconds to reach a height of 2 meters. The formula we can use is: Initial velocity = (Final velocity - Acceleration * Time). Plugging in the values, we get: Initial velocity = (0 - 9.8 * 0.2) = -1.96 m/s. However, since the rocket is launched vertically upwards, we take the magnitude of this velocity, which is 1.96 m/s. Therefore, the rocket was launched at a speed of 1.96 m/s.

To find the maximum height the rocket reaches, we can use the equation: Maximum height = Initial velocity^2 / (2 * Acceleration). Plugging in the values, we get: Maximum height = (1.96^2) / (2 * 9.8) = 16.1 meters. Therefore, the maximum height the rocket reaches is 16.1 meters.

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