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Answer :
the total charge of all the electrons in a 12-kg bar of gold is 4.6×[tex]10^8[/tex] C and the net charge of the bar is zero.
The following formula is used to get the total charge of all the electrons in the 12-kg bar of gold:
[tex]12 \text{ kg } Au \times \dfrac{1000 \text { g}}{1 \text{ kg}} \times \dfrac{1 \text { mol } Au}{197 \text{ g } Au} \times \dfrac{6.022 \times 10^{23} \text { atoms } Au}{1 \text{ mol } Au} \times \dfrac{79 \text { electrons}}{1 \text{ atom } Au} \times \dfrac{1.602 \times 10^{-19} \text { C}}{1 \text{ electron}} = 4.6 \times 10^8 \text{ C}[/tex]
The total charge of all the electrons in a 12-kg bar of gold is
4.6×[tex]10^8[/tex] C
Gold that is present in gold bars is pure gold. The charge of the gold bar's protons will balance the charge of its electrons. This indicates that the net charge will be equal to zero since the protons will have an equal but opposite charge to the electrons.
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