There are only red counters, blue counters, and green counters in a bag. There are 5 red counters, 6 blue counters, and 1 green counter. Jim puts some more green counters into the bag.

1. Work out the number of green counters that are now in the bag.

2. What is the probability of taking at random a red counter?

Question

10-05-2025
Mathematics

High School

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There are only red counters, blue counters, and green counters in a bag. There are 5 red counters, 6 blue counters, and 1 green counter. Jim puts some more green counters into the bag.

1. Work out the number of green counters that are now in the bag.

2. What is the probability of taking at random a red counter?

Answer :

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AnshikaP AnshikaP · Answer 1 · 2025-04-26T08:23:23-04:00

Final answer:

To find the number of green counters in the bag, add the number Jim added to the original number. The probability of selecting a red counter is 5/12.

Explanation:

To find the number of green counters in the bag after Jim adds more, we need to know how many he added. Once we have that information, we can simply add the number of green counters that were already in the bag to the number that Jim added.

For example, if Jim added 3 more green counters, then the total number of green counters in the bag would be 1 (original) + 3 (added) = 4.

To find the probability of randomly selecting a red counter, we need to know the total number of counters in the bag. In this case, we know that there are 5 red counters, 6 blue counters, and a certain number of green counters. Let's assume there are no other counters in the bag.

Therefore, the total number of counters would be 5 + 6 + 1 = 12. The probability of selecting a red counter would then be the number of red counters (5) divided by the total number of counters (12), which is 5/12.