All of the options below will cause an infinite loop EXCEPT:

1)
```
mov ecx, 0

L1:
mov eax, ecx
dec ecx
loop L1
```

2)
```
mov ecx, -1

L1:
mov eax, ecx
inc ecx
loop L1
```

3)
```
mov ecx, 0

L1:
mov eax, ecx
inc ecx
loop L1
```

4)
```
mov ecx, -1

L1:
mov eax, ecx
dec ecx
loop L1
```

Question

16-12-2024
Biology

High School

We appreciate your visit to All of the options below will cause an infinite loop EXCEPT 1 mov ecx 0 L1 mov eax ecx dec ecx loop L1 2 mov. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

All of the options below will cause an infinite loop EXCEPT:

1)
```
mov ecx, 0

L1:
mov eax, ecx
dec ecx
loop L1
```

2)
```
mov ecx, -1

L1:
mov eax, ecx
inc ecx
loop L1
```

3)
```
mov ecx, 0

L1:
mov eax, ecx
inc ecx
loop L1
```

4)
```
mov ecx, -1

L1:
mov eax, ecx
dec ecx
loop L1
```

Answer :

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prabhatrathi24se prabhatrathi24se · Answer 1 · 2024-02-22T19:00:48-05:00

Final answer:

The assembly code snippet that will not cause an infinite loop is the one with 'mov ecx, -1' followed by 'inc ecx', as this will increment ECX from -1 to 0, immediately terminating the loop.

Explanation:

The question asks which of the provided assembly code snippets will not cause an infinite loop. Each snippet uses a loop instruction that decrements the ECX register and branches to the label L1 if ECX is not zero. Let's analyze them:

mov ecx, 0 followed by dec ecx will result in ECX being decremented each time, eventually wrapping around to a large positive number, thus creating an infinite loop.
mov ecx, -1 followed by inc ecx will immediately terminate the loop because -1 is 0xFFFFFFFF in hexadecimal, and incrementing it will make ECX zero.
mov ecx, 0 followed by inc ecx will increment ECX each time, which would normally terminate the loop, but the eax is not affecting the loop condition.
mov ecx, -1 followed by dec ecx will create an infinite loop as ECX will always remain -1 (0xFFFFFFFF in hexadecimal), which is non-zero.

Therefore, the option that will NOT cause an infinite loop is the second one - incrementing ECX when it is initialized to -1.

All of the options below will cause an infinite loop EXCEPT:1) ```mov ecx, 0L1:mov eax, ecxdec ecxloop L1```2) ```mov ecx, -1L1:mov eax, ecxinc ecxloop L1```3) ```mov ecx, 0L1:mov eax, ecxinc ecxloop L1```4) ```mov ecx, -1L1:mov eax, ecxdec ecxloop L1```

Answer :

Final answer:

Explanation:

Other Questions

All of the options below will cause an infinite loop EXCEPT:

1)
```
mov ecx, 0

L1:
mov eax, ecx
dec ecx
loop L1
```

2)
```
mov ecx, -1

L1:
mov eax, ecx
inc ecx
loop L1
```

3)
```
mov ecx, 0

L1:
mov eax, ecx
inc ecx
loop L1
```

4)
```
mov ecx, -1

L1:
mov eax, ecx
dec ecx
loop L1
```