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Answer :
Final answer:
The mean time until the second egg is laid in a Poisson process where a hen lays eggs at an average rate of 1 egg per 28 hours is 56 hours, which is twice the mean time for one egg. Correct option is C 56 hours
Explanation:
The question posed involves a Poisson process in which the average rate of an event (hen laying eggs) is given. We must find the mean time until the second egg is laid given an average rate of 1 egg per 28 hours. When we deal with Poisson processes, the time between events follows an exponential distribution, and the average time until an event occurs is the reciprocal of the rate of the process. Since the mean time until one egg is laid is 28 hours, for the second egg, we essentially wait for two such 'events' to occur, hence the mean time will be twice the mean time for one egg.
The answer is:
Mean time until the 2nd egg is laid = 2 imes 28 hours = 56 hours.
Therefore, the correct answer is C) 56 hours.
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