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Answer :
Answer:
the percent yield is 78.2%
Explanation:
The balanced equation for the reaction is:
2 Al₂(SO4)3 + 3 Mg → 3 MgSO4 + 4 Al
The molar mass of Al₂(SO4)3 is 342.15 g/mol.
First, calculate the number of moles of Al₂(SO4)3 present:
312.7 g / 342.15 g/mol = 0.913 mol Al₂(SO4)3
According to the balanced equation, 2 moles of Al₂(SO4)3 produce 4 moles of Al:
0.913 mol Al₂(SO4)3 x (4 mol Al / 2 mol Al₂(SO4)3) = 1.826 mol Al
The theoretical yield of Al is therefore:
1.826 mol Al x 26.98 g/mol = 49.24 g Al
The percent yield is:
(actual yield / theoretical yield) x 100%
Substituting the given values:
(38.5 g Al / 49.24 g Al) x 100% = 78.2%
Therefore, the percent yield is 78.2%.
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