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A solid ball of mass 1.6 kg and diameter 10 cm is rotating about its diameter at 67 revolutions per minute. What is its kinetic energy?

Answer :

The KE of the solid ball is approximately 0.000879 Joules, where KE is the kinetic energy.

To calculate the kinetic energy of the solid ball, we need to use the formula:

KE = (1/2) * I * ω^2

where KE is the kinetic energy, I is the moment of inertia, and ω is the angular velocity.

For a solid ball rotating about its diameter, the moment of inertia can be calculated as:

I = (2/5) * m * r^2

where m is the mass of the ball and r is the radius (half of the diameter).

So, substituting the given values, we get:

r = 0.05 m
m = 1.6 kg
ω = (67 rev/min) * (2π rad/rev) * (1 min/60 s) = 7.03 rad/s

I = (2/5) * 1.6 kg * (0.05 m)^2 = 0.0004 kg m^2

KE = (1/2) * 0.0004 kg m^2 * (7.03 rad/s)^2 = 0.000879 J

Therefore, the kinetic energy of the rotating solid ball is approximately 0.000879 Joules.

Learn more about Kinetic energy here: brainly.com/question/26405082

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