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Assume that adults have IQ scores that are normally distributed with a mean of 98.1 and a standard deviation of 19. Find the first quartile \(Q_1\), which is the IQ score separating the bottom 25% from the top 75%.

Answer :

Final answer:

To find the first quartile, calculate the z-score and use the z-score table to find the corresponding IQ score.

Explanation:

To find the first quartile, we need to calculate the z-score corresponding to the bottom 25% of the distribution. The z-score can be calculated using the formula:

z = (X - μ) / σ

where X is the IQ score, μ is the mean, and σ is the standard deviation.

After calculating the z-score, we can use the z-score table to find the corresponding IQ score. The first quartile (Q1) is the value separating the bottom 25% from the top 75% of the distribution.

In this case, since the mean is 98.1 and the standard deviation is 19, we can calculate the z-score as follows:

z = (Q1 - 98.1) / 19 = -0.674

From the z-score table, we find that the corresponding percentile is 0.2500. This means that the first quartile IQ score, Q1, is the IQ score that separates the bottom 25% from the top 75% of the distribution.

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