We appreciate your visit to In an emergency stop a driver applies the brakes in a car traveling at 24 m s The car stops after traveling 19 2 m. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The average acceleration (in fact, deceleration, or negative acceleration) of the car during the emergency stop is 14.4 m/s^2.
Explanation:
In Physics, acceleration is defined as the rate of change of velocity per unit of time. When a vehicle comes to an emergency stop, it undergoes a form of acceleration known as deceleration, or negative acceleration. Given the initial speed of the car (24 m/s), the stopping distance (19.2 m), and knowing the final speed is 0 m/s, we can use the kinematic equation, v^2 = u^2 + 2as, where v is the final speed, u is the initial speed, a is the acceleration, and s is the distance travelled.
Substituting the given values into the equation gives us 0 = (24 m/s)^2 + 2*a*19.2 m. Solving for 'a' we find that a = - (24 m/s)^2 / (2*19.2 m) = -14.4 m/s^2. Thus, the average deceleration (or negative acceleration) of the car during the emergency stop is 14.4 m/s^2.
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