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Answer :
The total vapor pressure of the mixture is 124.5 torr.
Given:
Vapor pressure of hexane (P_hexane) = 151.4 torr
Vapor pressure of cyclohexane (P_cyclohexane) = 97.6 torr
Since we are mixing equal quantities of moles of hexane and cyclohexane, the mole fraction of each component in the mixture is 0.5.
Using Raoult's law, the total vapor pressure of the mixture (P_total) is calculated as follows:
P_total = (mole fraction of hexane) * (vapor pressure of hexane) + (mole fraction of cyclohexane) * (vapor pressure of cyclohexane)
P_total = (0.5 * 151.4 torr) + (0.5 * 97.6 torr)
P_total = 75.7 torr + 48.8 torr
P_total = 124.5 torr
Therefore, the total vapor pressure of the mixture is 124.5 torr.
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