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XYZ Company is producing a solar panel for street lighting, composed of 80 solar cells. The company has 10 solar tabber and stringer machines, which solder and assemble the cells to create the photovoltaic cell at a rate of 50 pieces per hour. The man-machine ratio is 1:1. Currently, the company has 6 technicians per shift, working 3 shifts a day with a 75-minute break. They work 5 days a week and 4 weeks a month.

a) How many panels can they produce in one month?

b) What will be the lost panels if 2 workers of the 2nd shift are suspended for 2 days in Week 2?

c) What will be the lost panels if all workers attend a 3-day training from 9 am to 8 pm daily in Week 2 and a 2-day training from 4 pm to 11 pm in Week 3?

Power failure occurred from 1:25 am to 5:20 am on Day 4. Find the lost capacity.

Answer :

a) The total panels produced in a month is 1,440,000. b) Number of panels lost due to the 2 workers on the second shift for two days of week 2 -12,000 solar panels. c)25,000 solar panels.d) 17,750 solar panels.

a) The company has 10 solar tabber and stinger machines at any given time. The solar tabber and stringer machines allow to solder and assemble the cells together in order to compose the photovoltaic cell at the rate of 50 pcs per hour. So, in one hour, they can produce 50*10=500 solar cells.

In one shift, they can produce solar cells for 6*500 = 3,000 solar cells. Since the man machine ratio is 1:1, there are 6 technicians per shift and so they can produce 3,000 panels per shift.There are 3 shifts per day with a 75-minute break which means that a total of 24 hours are worked every day. They produce 3,000 panels in one shift, therefore they will produce 3,000*24= 72,000 panels in one day. The total panels produced in a month is therefore: 72,000*20=1,440,000.

b) Number of panels lost due to the 2 workers on the second shift for two days of week 2

= 2 days * 2 workers/day * 3,000 solar panels

= 12,000 solar panels.

c) The total number of training days is 3 + 2 = 5 days. The time of the training is 9am to 8pm and 4 pm to 11 pm for 3 days and 2 days, respectively. The number of hours in the first training is 11-9 = 2 hours in the morning and 12-4 = 8 hours in the afternoon. The number of working hours lost per day is, therefore, 2+8 = 10 hours. The number of panels lost per day due to the training is: 10 hours * 50 solar panels/hour * 10 machines = 5,000 solar panels per day. Therefore, for the 5 days of training, the total panels lost= 5 days * 5,000 solar panels

= 25,000 solar panels.

d) The time of the power failure is from 1:25 am to 5:20 am. This means that the power failure lasted for 5 hours and 55 minutes. The number of panels lost = 5 hours and 55 minutes * 50 solar panels/hour/machine * 10 machines

= 17,750 solar panels.

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