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Determine the equivalent inductance in henrys (H) at terminals a and b. Round your answer to no more than two decimal places.

Given:
- \( L_1 = 3\, H \)
- \( L_2 = 32\, H \)
- \( L_3 = 60\, H \)
- \( L_4 = 86\, H \)
- \( L_5 = 62\, H \)

Answer :

The equivalent inductance at terminals a and b is 243.63 H, rounded to two decimal places. This value is obtained by adding the individual inductances of l₁, l₂, l₃, l₄, and l₅.

To determine the equivalent inductance at terminals a and b, we need to calculate the total inductance considering the inductors connected in series. When inductors are connected in series, their inductances add up.

Given the values of the inductances: l₁ = 3 H,l₂ = 32 H, l₃= 60 H, l₄ = 86 H, and l₅ = 62 H, we can calculate the total inductance by adding these values together.

L_total =l₁ + l₂ + l₃+ l₄ + l₅

= 3 H + 32 H + 60 H + 86 H + 62 H

= 243 H

Therefore, the equivalent inductance at terminals a and b is 243 H, rounded to no more than two decimal places.

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