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Answer :
The same projectile needs the power to accelerate from rest to a launch speed of 2v at a time of 219.6 W.
Calculation-
power P = work/time
= ½mv² / t
P' = ½m(2v)²/t
= 4 * ½mv² / t
= 4 * P
so
P' = 4 * 54.9W
= 219.6 W (or 220 W rounded off)
What is the projectile's acceleration at the pinnacle of its trajectory?
As a result, from the moment the projectile is hurled, through its greatest point, and until it touches the earth, its acceleration is 9.81 meters per second per second, or equal to the acceleration caused by gravity.
to know more about accelerating here:
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