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Answer :
When the 13.99 mL of the HCl of unknown concentration are with the 13 mL of the 2.14 M NaOH, The molarity of HCl is 1.98 M
The balance reaction is as follows :
NaOH + HCl --> NaCl + H₂O
The concentration, M1 = ?
The volume V1 = 13.99 mL
The concentration , M2 = 2.14 M
The volume , V2 = 13 mL
The expression is given as :
M1 V1 = M2 V2
M1 = M2 V2 / V1
M1 = ( 2.14 × 13 ) / 13.99
M1 = 1.98 M
Thus, the molarity of the HCl is 1.98 M.
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