High School

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Penny's solving work is shown here. Has she solved this equation correctly?

Line 1: [tex]\quad \frac{3}{5} y - 8 = 4[/tex]

Line 2: [tex]\frac{5}{3} \cdot \frac{3}{5} y = 12 \cdot \frac{5}{3}[/tex]

Line 3:
[tex]
\begin{array}{l}
y = \frac{60}{3} \\
y = 20
\end{array}
[/tex]

Answer :

Sure! Let's solve Penny's problem step by step to see if she has done it correctly.

### Step-by-Step Solution:

Line 1:
[tex]\[
\frac{3}{5} y - 8 = 4
\][/tex]

1. Add 8 to both sides:
To isolate the term with [tex]\( y \)[/tex], add 8 to both sides of the equation:

[tex]\[
\frac{3}{5} y - 8 + 8 = 4 + 8
\][/tex]

[tex]\[
\frac{3}{5} y = 12
\][/tex]

2. Multiply by the reciprocal:
Multiply both sides by the reciprocal of [tex]\( \frac{3}{5} \)[/tex] to solve for [tex]\( y \)[/tex]:

[tex]\[
y = 12 \times \frac{5}{3}
\][/tex]

[tex]\[
y = 20
\][/tex]

Penny correctly finds [tex]\( y = 20 \)[/tex] from Line 1.

Line 2:
[tex]\[
\frac{5}{3} \cdot \frac{3}{5} y = 12 \cdot \frac{5}{3}
\][/tex]

1. Simplify the left side:
[tex]\(\frac{5}{3} \times \frac{3}{5} y\)[/tex] simplifies to [tex]\(y\)[/tex] because [tex]\(\frac{5}{3} \times \frac{3}{5} = 1\)[/tex].

2. Simplify the right side:
Calculate [tex]\( 12 \times \frac{5}{3} \)[/tex]:

[tex]\[
12 \times \frac{5}{3} = 20
\][/tex]

So, the equation simplifies to:

[tex]\[
y = 20
\][/tex]

Penny also finds [tex]\( y = 20 \)[/tex] correctly in Line 2.

Conclusion:

Penny solved both equations correctly, and both approaches lead to the same solution:
[tex]\( y = 20 \)[/tex]

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