High School

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Given the reactions:

1. Sr(NO₃)₂(aq) + Na₂SO₄(aq) →
- Ionic:
- Net-Ionic:

2. Sr(NO₃)₂(aq) + NaOH(aq) →
- Ionic:
- Net-Ionic:

3. Sr(NO₃)₂(aq) + Na₂S(aq) →
- Ionic:
- Net-Ionic:

4. Fe(NO₃)₃(aq) +

The missing product is:
A. H₂SO₄
B. NaNO₃
C. SrS
D. NaNO₂

Answer :

The missing product for the reaction between Sr(NO3)2 and Na2S is SrS, which forms as a precipitate. To answer such questions, one must apply solubility rules and construct net-ionic equations by identifying the reacting ions that form the product. The correct option is(C).

The provided with several chemical reaction equations and asked to identify missing products or write full ionic and net-ionic equations. Additionally, some background information and solutions are given for reference and to aid in writing the net-ionic equations.

For the reaction between Sr(NO3)2 and Na2S, the missing product is SrS, because when Sr2+ ion reacts with S2- ion, they form the precipitate SrS. The complete balanced equation is Sr(NO3)2(aq) + Na2S(aq)

ightarrow 2NaNO3(aq) + SrS(s), and the net-ionic equation is Sr2+(aq) + S2-(aq)
ightarrow SrS(s). For other reactions like Fe(NO3)3 with NaOH and Al2(SO4)3 with BaCl2, the key is to remember the solubility rules and the formation of precipitates to write the net-ionic equations correctly.

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