High School

We appreciate your visit to A block of mass 50 kg slides over a horizontal distance of 1 m If the coefficient of friction between their surfaces is 0 2. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A block of mass 50 kg slides over a horizontal distance of 1 m. If the coefficient of friction between their surfaces is 0.2, then the work done against friction is:

(a) 49 J
(b) 98 J
(c) 196 J
(d) 245 J

Answer :

Final answer:

Final answer

The work done against friction is 98 J. Hence, the correct option is (b) 98 J.

Explanation:

To calculate the work done against friction, we need to know the force of friction, which is the product of the mass of the block, gravitational acceleration (g), and the coefficient of friction. The gravitational acceleration on Earth is approximately 9.8 m/s2. The force of friction (f) can be calculated using the formula f =

coefficient of friction (

0.2)

\times mass (50 kg)

\times g (9.8 m/s2). The work done (W) by this force over a horizontal distance of 1 m is then W = f

\times distance, which gives us 98 J. This is the energy required to overcome the force of friction while the block slides for 1 m.

Thanks for taking the time to read A block of mass 50 kg slides over a horizontal distance of 1 m If the coefficient of friction between their surfaces is 0 2. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada