High School

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**Data Analysis Task**

**Data:**
- 1: 97.3, 16.9, 8.3
- 1: 106.4, 20.2, 7.2
- 1: 118.2, 20.1, 6.3
- 1: 99.7, 15.7, 7.3
- 1: 106.5, 13.9, 8.7
- 1: 84.2, 14.9, 8.7
- 2: 44.9, 7.9, 4.7
- 2: 46.1, 12.5, 6.1
- 2: 59.3, 15.5, 5.0
- 2: 35.5, 10.2, 5.8
- 2: 50.7, 8.9, 6.6
- 2: 56.8, 13.3, 8.4
- 3: 88.0, 18.0, 8.0
- 3: 119.8, 18.5, 8.3
- 3: 65.8, 9.2, 7.6
- 3: 82.9, 18.8, 6.4
- 3: 149.9, 22.8, 8.2
- 3: 117.1, 17.5, 7.7

**Description:**
- Comparison of 3 fixation methods with respect to 3 responses, with 6 replicates (knees) per method.

**Methods:**
- 1 = Vertical Suture
- 2 = Meniscus Arrow
- 3 = FasT-Fix

**Responses:**
- Load at failure (N)
- Displacement (mm)
- Stiffness (N/mm)

**Variables/Columns:**
- Method: Column 8
- Load at Failure: Columns 10-16
- Displacement: Columns 18-24
- Stiffness: Columns 26-32

**Instructions:**
Using statistical software (e.g., SPSS) to analyze the data and generate outputs.

**Required Analysis:**
- ANOVA and Post Hoc test (S-N-K)

**Tasks:**
1. Set up hypotheses:
- \( H_0 \): \( \mu_1 = \mu_2 = \mu_3 \)
- \( H_a \): There are some differences in means \( \mu_1, \mu_2, \) and \( \mu_3 \)

2. Find the P-value.

3. Decision:
- What is your decision based on the P-value?

4. Interpretation:
- What kind of difference in means is observed?

5. Calculate and interpret the P-value.

6. Provide a detailed interpretation of the results.

Answer :

An ANOVA (Analysis of Variance) test was conducted to compare three fixation methods (Vertical Suture, Meniscus Arrow, and FasT-Fix) with respect to three responses (Load at failure, Displacement, and Stiffness). The data consisted of 6 replicates (knees) per method. The hypothesis test aimed to determine if there were significant differences in means between the three methods. Statistical software (SPSS) was used for the analysis.

To conduct the ANOVA test, the null hypothesis (H0) was set as "the means of Load at failure, Displacement, and Stiffness are equal for all three fixation methods." The alternative hypothesis (Ha) stated that there are some differences in means between the methods.

The P-value obtained from the ANOVA analysis will indicate the statistical significance of the differences. If the P-value is less than the chosen significance level (typically 0.05), the null hypothesis will be rejected, suggesting that there are significant differences in means.

Based on the P-value obtained from the analysis, a decision can be made. If the P-value is less than 0.05, the decision would be to reject the null hypothesis, indicating that there are significant differences in means between the methods. If the P-value is greater than 0.05, the decision would be to fail to reject the null hypothesis, suggesting that there is not enough evidence to conclude significant differences in means.

The interpretation of the results will depend on the obtained P-value. If the P-value is small (less than 0.05), it suggests that at least one of the fixation methods significantly differs from the others in terms of Load at failure, Displacement, or Stiffness. If the P-value is not small (greater than 0.05), it indicates that there is insufficient evidence to conclude significant differences between the methods.

Learn more about null hypothesis here:

https://brainly.com/question/32386318

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