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The arrow on a crossbow undergoes uniform acceleration over a distance of 38.1 cm. If the acceleration takes place over [tex]8.93 \times 10^{-3} \text{ s}[/tex] and the arrow is initially at rest, what is the arrow’s final speed?

Answer :

Final answer:

The arrow's final speed after undergoing uniform acceleration is 0 m/s.

Explanation:

The final speed of the arrow can be found using the equation: final speed = initial speed + (acceleration x time). In this case, the initial speed is 0 m/s since the arrow is initially at rest, and the acceleration can be calculated using the formula: acceleration = (final speed - initial speed) / time. Plugging in the given values, we have:

acceleration = (final speed - 0 m/s) / (8.93 x 10³ s)

Solving for the acceleration, we get:

acceleration = final speed / (8.93 x 10³ s)

Thus, we can rewrite the initial equation as:

final speed = 0 m/s + (acceleration x time)= 0 m/s + (final speed / (8.93 x 10³ s) x 8.93 x 10³ s)= final speed

Therefore, the final speed of the arrow is 0 m/s.

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