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Answer :
Final answer:
There are 8.25014 \\u00d7 1023 atoms of phosphorus in 1.37 moles of phosphorus trichloride when calculated using Avogadro's number.
Explanation:
To determine the number of atoms of phosphorus in 1.37 moles of phosphorus trichloride (PCl3), we can use Avogadro's number, which is 6.022 \\u00d7 1023 atoms per mole. Since each molecule of phosphorus trichloride contains one atom of phosphorus, we simply multiply the number of moles of PCl3 by Avogadro's number.
The calculation is as follows: 1.37 moles of PCl3 \\u00d7 6.022 \\u00d7 1023 atoms/mole = 8.25014 \\u00d7 1023 atoms of phosphorus Therefore, there are 8.25014 \\u00d7 1023 atoms of phosphorus in 1.37 moles of phosphorus trichloride.
The number of atoms of phosphorus in 1.37 moles of phosphorus trichloride can be calculated by looking at the chemical formula of the compound. In one molecule of PCl3, there is 1 atom of phosphorus. Therefore, in 1.37 moles of PCl3, there are 1.37 moles of phosphorus atom
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