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For the following reaction, 19.1 grams of carbon dioxide are allowed to react with 38.6 grams of potassium hydroxide.

What is the maximum amount of potassium carbonate that can be formed?

Answer :

Final answer:

By identifying the limiting reactant (carbon dioxide, in this case) and calculating using stoichiometry and molar mass, we can determine that the maximum amount of potassium carbonate that can be formed from the reaction of 19.1g of carbon dioxide and 38.6g of potassium hydroxide is approximately 59.44 grams.

Explanation:

The question pertains to the chemical reaction between carbon dioxide and potassium hydroxide forming potassium carbonate. From the given information, the reaction is as follows: 2 KOH + CO2 -> K2CO3 + H2O. Using the molar masses of each compound involved, we can calculate that 19.1 grams of CO2 is approximately 0.43 moles and 38.6 grams of KOH is approximately 0.69 moles. The stoichiometry of the reaction indicates that the ratio of KOH to CO2 is 2:1. Since we have less CO2 (the limiting reactant), we are able to produce a maximum of 0.43 moles of K2CO3. Given that the molar mass of K2CO3 is 138.21 g/mol, we can multiply to find that we can produce a maximum of approximately 59.44 grams of K2CO3.

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