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The mean mass of 500 kudu at a private game park is 151 kg, and the standard deviation is 15 kg. Assume there is a normal distribution of the masses.

a) Calculate the proportion of kudus that have an average mass between 120 kg and 155 kg.

b) Calculate the percentage of kudus that have an average mass greater than 185 kg.

Answer :

Final answer:

The proportion of kudus that weigh between 120 and 155 kg is 0.5872, while 1.13% of kudus weigh more than 185 kg. This calculation uses the z-score formula and looks up the corresponding proportions in the standard normal distribution table.

Explanation:

This question involves knowledge of normal distribution. We first need to calculate the z-scores corresponding to the given weights. The formula for the z-score is: (X - μ)/σ where X is the data point, μ is the mean, and σ is the standard deviation.

  1. a) The proportion of kudus with a mass between 120 and 155 kg. Z-scores for 120 kg and 155 kg are (120 - 151)/15 = -2.07 and (155-151)/15 = 0.27 respectively. According to the standard normal distribution table, the proportions corresponding to these z-scores are 0.0192 and 0.6064. Hence, the proportion of kudus that weigh between 120 and 155 kg is 0.6064 - 0.0192 = 0.5872.
  2. b) To find out the percentage of kudus that weigh more than 185 kg, calculate the z-score for 185 kg which is (185-151)/15 = 2.27. The proportion corresponding to this z-score is 0.9887. So, the percentage of kudus that weigh more than 185 kg is (1 - 0.9887) * 100% = 1.13%.

Therefore, the proportion of kudus that weigh between 120 and 155 kg is 0.5872, while 1.13% of kudus weigh more than 185 kg under the assumption of a normal distribution.

Learn more about Normal Distribution here:

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