High School

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A person of mass 94 kg is standing in a lift which is accelerating upwards at 0.54 m/s -2. draw a diagram to show thge forces acting on the person and calculate the force, f, the person exerts on the floor of the lift

Answer :

The force, f, that the person exerts on the floor of the lift is 973.84 N.

Given that the lift is moving upwards, then its motion is against the force of gravity.

So that;

from the second equation of motion;

f = ma

we have;

f = mg - ma

since g > a

f = m(g - (-a))

= m(g + a)

m = 94 kg, a = 0.54 [tex]m/s^{2}[/tex], g = 9.82 [tex]m/s^{2}[/tex].

Then,

f = 94 (9.82 + 0.54)

= 973.84

f = 973.84 N

The force, f, the person exerts on the floor of the lift is 973.84 N.

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