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Answer :
Final answer:
To warm 0.455 kg of masa from 41°C to the temperature of the oil at 182°C, 118 kJ of thermal energy is required, calculated using the specific heat capacity equation.
Explanation:
To calculate the thermal energy required to warm 0.455 kg of masa to the temperature of the oil, we can use the specific heat capacity equation:
Q = mcΔT,
where Q is the thermal energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
The specific heat of masa is given as 1850 J/(kg·K), the initial temperature (T1) is 41°C, and the final temperature (T2) is 182°C. The change in temperature (ΔT) is
T2 - T1 = 182°C - 41°C
= 141°C.
Now, we calculate the energy:
Q = (0.455 kg) x (1850 J/kg·K) x (141 K)
= 118455.5 J.
Therefore, it would require 118 kJ (rounded to three significant figures) of thermal energy to warm 0.455 kg of masa to the temperature of the oil.
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