High School

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Mr. Lim had a bag of sweets. After giving each pupil 7 sweets, he had 4 sweets left. If he had given only 5 sweets to each pupil, he would have 80 sweets left.

i. How many pupils were there in the class?

ii. How many sweets did Mr. Lim have?

Answer :

Solving a system of equations we can see that there are 270 sweets and 38 pupils.

How many pupils and sweets are there?

Let's define the variables:

P = number of pupils.

S= number of sweets.

With the given information, we can write:

7*P + 4 = S

5*P + 80 = S

So we have a system of equations, now we can write:

7*P + 4 = S = 5*P + 80

Solving that for P:

7*P + 4 = 5*P + 80

7*P - 5*P = 80 - 4

2*P = 76

P = 76/2 = 38

There are 38 pupils, and the number of sweets is given by:

S = 7*P + 4 = 7*38 + 4 = 270

If you want to learn more about systems of equations:

https://brainly.com/question/14323743

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