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Answer :
Answer:
2 and 3
Step-by-step explanation:
Given:
- a- first term, d- common difference
- Sum of the first 4 terms: S₁₋₄= 30
- Sum of the last 4 terms: S₄₋₇= 66
S₁₋₄= 4/2(2a+3d)=4a+6d= 30
⇒ 2a+3d=15
S₄₋₇= S₇ - S₃= 7/2(2a+6d)- 3/2(2a+2d)= 7a+21d - 3a - 3d= 4a+18d=66
⇒ 2a+9d= 33
Comparing the 2 equations:
- 2a+3d= 15
- 2a+9d= 33
- 9d-3d= 33-15
- 6d= 18
- d=3
- 2a+3*3=15
- 2a= 6
- a=2
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