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A collection of 59 identical metal coins, each with a diameter of 1.57 inches and a thickness of 0.0787 inches, is found to have a total weight of 6.322 lbs. What is the density (in g/ml) of the metal?

Answer :

The density (in g/ml) of the metal 268700 g/m³.

To find the density of the metal, we need to know the mass and volume of the coins. We can calculate the volume of one coin and then multiply by the number of coins to get the total volume.

The volume of one coin can be found using the formula for the volume of a cylinder:

V = π × r² × h

where r is the radius and h is the height (thickness) of the coin.

r = 1.57 inches / 2 = 0.785 inches

h = 0.0787 inches

V = π × 0.785² × 0.0787 = 0.0109 cubic inches

Since 1 cubic inch = 16.387064 cm³, the volume of one coin is 0.0109 × 16.387064 = 0.179 cm³.

The total volume of the 59 coins is 0.179 × 59 = 10.58 cm³.

The mass of the coins is 6.322 lbs = 2834.9 g.

So the density of the metal is:

density = mass / volume

density = 2834.9 g / 10.58 cm³

density = 268.7 g/cm³ = 268700 g/m³

Therefore, the density of the metal is 268700 g/m³

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