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An object is thrown upward at a speed of 97 feet per second by a machine from a height of 18 feet off the ground. The height of the object after [tex]t[/tex] seconds can be found using the equation [tex]h = 16t^2 + 97t + 18[/tex].

What is the height of the object after 3 seconds?

A) 48 feet
B) 144 feet
C) 432 feet
D) 768 feet

Answer :

Final answer:

To find the height of the object after 3 seconds, substitute t=3 into the equation h=16t^2 to get 144 feet. The correct option is B.

Explanation:

The height of the object after 3 seconds can be found by substituting t=3 into the equation h=16t^2.

h=16*(3)^2
h=16*9
h=144 feet

Therefore, the height of the object after 3 seconds is 144 feet.

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