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At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press.

Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8} x = 224 ; x = 196[/tex] pounds

B. [tex]\frac{7}{8} x = 224 ; x = 256[/tex] pounds

C. [tex]\frac{7}{8} = \frac{x}{224} ; x = 196[/tex] pounds

D. [tex]\frac{7}{8} = \frac{x}{224} ; x = 256[/tex] pounds

Answer :

Sure, let's solve this step-by-step.

We are given that Jasper could bench press 224 pounds, which is [tex]\(\frac{7}{8}\)[/tex] of the weight that Balin could bench press. We need to find out how much weight Balin could bench press, denoted by [tex]\(x\)[/tex].

The relationship given in the problem can be written as an equation:
[tex]\[ \frac{7}{8}x = 224 \][/tex]

We're solving for [tex]\(x\)[/tex], so we need to isolate [tex]\(x\)[/tex]. To do this, divide both sides of the equation by [tex]\(\frac{7}{8}\)[/tex]:

[tex]\[ x = \frac{224}{\frac{7}{8}} \][/tex]

Dividing by a fraction is the same as multiplying by its reciprocal. The reciprocal of [tex]\(\frac{7}{8}\)[/tex] is [tex]\(\frac{8}{7}\)[/tex]. So, we can rewrite the equation as:

[tex]\[ x = 224 \times \frac{8}{7} \][/tex]

Now, carry out the multiplication:

[tex]\[ x = 224 \times \frac{8}{7} \][/tex]
[tex]\[ x = 224 \times \frac{8}{7} = 224 \times \frac{8}{7} = 224 \div 1 \times \frac{8}{7}\][/tex]
[tex]\[ x = 224 \div 1 \times 8 \div 7 = 1792 \div 7 = 256\][/tex]

So, [tex]\(x\)[/tex] = 256 pounds.

From the given options, the correct answer is:
[tex]\[ \frac{7}{8} x=224 ; x=256 \][/tex] pounds.

This option correctly shows the equation as [tex]\(\frac{7}{8} x = 224\)[/tex] and the correct value of [tex]\(x\)[/tex] as 256 pounds.

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