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Answer :
Final answer:
For an integer x to satisfy the conditions of leaving a remainder of 4 when divided by 5, and a remainder of 0 when divided by 9, it must conform to the structure of both 5n+4 = x and 9m = x, where n and m are integers. Out of the given options, only 36 meets both conditions.
Explanation:
The question is asking us for a possible value of x such that it satisfies the conditions: when divided by 5 the remainder is 4, and when divided by 9, the remainder is 0. Thus, x should conform to the structure of both 5n+4 = x and 9m = x, where n and m are integers. Looking at the given options, we can examine each one. The number 14 leaves a remainder of 4 when divided by 5 but a remainder of 5 when divided by 9, hence it does not satisfy both conditions. The numbers 23 and 27 do not satisfy the condition of leaving a remainder of 0 when divided by 9 either. However, 36 satisfies both conditions: it leaves a remainder of 4 when divided by 5 (because 5*7+4 = 36) and 36 divided by 9 is exactly 4 with a remainder of 0. Therefore, among the given options, 36 is the correct answer.
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