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If an 80.0 L cylinder is filled with 4.00 g of N₂, 6.00 g of O₂, and 8.00 g of CO₂ at a temperature of 600 K, what is the total pressure inside the cylinder?

A. 11.1 atm
B. 4.55 atm
C. 1.86 atm
D. 0.764 atm
E. 0.315 atm

Answer :

Final answer:

To find the total pressure in the cylinder, we calculate the moles of each gas, sum them up, and then use the Ideal Gas Law equation (P = nRT/V) to find the total pressure. In this case, the total pressure is 3.79 atm, which doesn't match any of the given choices.

Explanation:

To calculate the total pressure in the cylinder, we must find the moles of each gas using their respective molar masses.

The molar mass of N2, O2, CO2 are 28.01g/mol, 32.00g/mol, 44.01g/mol, respectively:

  • N2: 4.00g / 28.01g/mol = 0.1428 moles
  • O2: 6.00g / 32.00g/mol = 0.1875 moles
  • CO2: 8.00g / 44.01g/mol = 0.1818 moles

Next, using the ideal gas law equation P = nRT/V, with R = 0.0821 atm L/mol K:

Total moles of all gases = 0.1428 + 0.1875 + 0.1818 = 0.5121 moles

So, the total pressure, P = (0.5121 moles * 0.0821 atm L/mol K * 600 K) / 80.0 L = 3.79 atm

So, none of the given choices is correct: a. 11.1 atm b. 4.55 atm c. 1.86 atm d. 0.764 atm e. 0.315 atm.

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