Answer :

Final answer:

To find the frequency of a photon with an energy of 6.00x10^-15 Joules, use the equation E = hf, rearranged as f = E/h. The frequency is approximately 9.05 x 10^18 Hz when using Planck's constant.

Explanation:

The correct answer is: to calculate the frequency of a photon given its energy, we use the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency. Planck's constant (h) is 6.626 × 10-34 J·s. To find the frequency, we rearrange the equation to f = E/h.

Using the given energy of the photon, 6.00× 10-15 Joules, we calculate the frequency as follows:

f = E/h = (6.00× 10-15 J)/(6.626 × 10-34 J·s) ≈ 9.05 × 1018 Hz.

The correct answer is option Physics.

First, let's use the equation E = hf, where E is the energy, h is Planck's constant (6.626 × 10-34 J·s), and f is the frequency of the photon.

Plugging in the given energy of 6.00x10-15 Joules, we get:

E = (6.626 × 10-34 J·s) * f = 6.00x10-15 J

Dividing both sides by Planck's constant, we find:

f = 6.00x10-15 J / (6.626 × 10-34 J·s) = 9.07x1018 Hz

Therefore, the frequency of the photon is 9.07x1018 Hz.

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