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Answer :
Certainly! Let's solve the equation [tex]\(3x^2 = 27\)[/tex] step-by-step:
1. Simplify the Equation:
Start with the given equation:
[tex]\[
3x^2 = 27
\][/tex]
To simplify, divide both sides of the equation by 3:
[tex]\[
x^2 = \frac{27}{3}
\][/tex]
This simplifies to:
[tex]\[
x^2 = 9
\][/tex]
2. Solve for [tex]\(x\)[/tex]:
Now, we need to find the value of [tex]\(x\)[/tex] that satisfies the equation [tex]\(x^2 = 9\)[/tex].
To do this, take the square root of both sides of the equation:
[tex]\[
x = \sqrt{9}
\][/tex]
The square root of 9 can be either positive or negative, so there are two solutions:
[tex]\[
x = 3 \quad \text{or} \quad x = -3
\][/tex]
3. Solution:
Therefore, the solutions to the equation [tex]\(3x^2 = 27\)[/tex] are [tex]\(x = 3\)[/tex] and [tex]\(x = -3\)[/tex].
If you have any more questions or need further help, feel free to ask!
1. Simplify the Equation:
Start with the given equation:
[tex]\[
3x^2 = 27
\][/tex]
To simplify, divide both sides of the equation by 3:
[tex]\[
x^2 = \frac{27}{3}
\][/tex]
This simplifies to:
[tex]\[
x^2 = 9
\][/tex]
2. Solve for [tex]\(x\)[/tex]:
Now, we need to find the value of [tex]\(x\)[/tex] that satisfies the equation [tex]\(x^2 = 9\)[/tex].
To do this, take the square root of both sides of the equation:
[tex]\[
x = \sqrt{9}
\][/tex]
The square root of 9 can be either positive or negative, so there are two solutions:
[tex]\[
x = 3 \quad \text{or} \quad x = -3
\][/tex]
3. Solution:
Therefore, the solutions to the equation [tex]\(3x^2 = 27\)[/tex] are [tex]\(x = 3\)[/tex] and [tex]\(x = -3\)[/tex].
If you have any more questions or need further help, feel free to ask!
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