High School

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If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 feet per second, then its height \( h(f) \) after \( f \) seconds is given by the equation:

\[ h(f) = -16f^2 + 128f \]

(assuming air resistance is neglected).

What is the height of the rocket after 1 second?

Answer :

Final answer:

The height of the rocket after 1 second, when using the function h(f) = -16f² + 128f and substituting f with 1, is 112 feet.

Explanation:

To find the height of the rocket after 1 second, we can simply plug the value f = 1 into the given height function h(f) = -16f² + 128f. By substituting f with 1, we get:

h(1) = -16(1)² + 128(1)

h(1) = -16 + 128

h(1) = 112

Therefore, the height of the rocket after 1 second is 112 feet.

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