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What is the output of the following code snippet? multiset mymultiset; (41); (71); (71); (71); (15); multiset::iterator it; for (it = (); it != (); it++) { cout << " " << *it; } A 15 41 71 B 15 41 71 71 71 C 41 71 71 71 15 D 41 71 15

Answer :

Final answer:

The probable output of a well-formed code similar to the provided snippet, using a multiset data structure in C++, would be '15 41 71 71 71' because multisets in C++ are ordered collections and store values in ascending order, including duplicates. Option(B)

Explanation:

The given code snippet is an example of the multiset data structure in C++ which supports duplicate values. But some parts of the given code are missing which makes it difficult to predict the exact output. Presumably, if we had a complete code like the following:

multiset mymultiset={41,71,71,71,15}; for (multiset::iterator it = mymultiset.begin(); it != mymultiset.end(); it++) { cout << ' ' << *it; }

The output would be: 15 41 71 71 71. This is because multisets in C++ are ordered collections and store values in ascending order. Therefore, the numerals 15, 41, and 71 would be arranged in this same order, regardless of their original input order, with the numeral 71 repeated three times as per its frequency in the input.

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