Answer :

Final answer:

The calculation of 1.26 moles is correct for 98.3 grams of aluminum hydroxide after determining the molar mass of aluminum hydroxide and using it to convert grams to moles.

Explanation:

To determine how many moles are in 98.3 grams of aluminum hydroxide (Al(OH)3), you first need to calculate its molar mass. The molar mass of aluminum hydroxide is the sum of the molar masses of its constituent elements: Al, O, and H. Specifically, aluminum has a molar mass of 26.98g/mol, oxygen has a molar mass of 16.00g/mol, and hydrogen has a molar mass of 1.01g/mol. Aluminum hydroxide is composed of one aluminum atom, three oxygen atoms, and three hydrogen atoms, so its molar mass is:

(1 * 26.98g/mol) + (3 * 16.00g/mol) + (3 * 1.01g/mol) = 26.98g/mol + 48.00g/mol + 3.03g/mol = 78.01g/mol.

Next, you can use this molar mass to convert grams to moles:

98.3g Al(OH)3 × (1 mol Al(OH)3 / 78.01g Al(OH)3) = 1.26 moles Al(OH)3.

Thus, your calculation of 1.26 moles is correct based on the given mass of aluminum hydroxide.

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Rewritten by : Barada

yes your answer is correct the answer is 1.26

solution is moles=mass/molar mass =98.3/78=1.26