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Answer :
Final answer:
The question relates to Graham's Law of Effusion in chemistry. Using the given data for the time it takes for CH4 to effuse, we can calculate the time it takes for helium to effuse. Additionally, partial information suggests a real gas density calculation, but complete data is missing.
Explanation:
The question involves a concept related to Graham's Law of Effusion, which, in a simplified version, states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. You have the molar mass of CH4 (methane) which is 16 grams/mole, and helium (He) which is 4 grams/mole.
Applying Graham's law, we can calculate the rate of effusion for helium gas using the formula: Rate1/Rate2 = sqrt(M2/M1), where Rate1 is for CH4, M1 is the molar mass of CH4, Rate2 is for helium, and M2 is the molar mass of helium.
If we consider the time for CH4 to be 12 seconds (as given), we find that the time for helium to effuse would be: sqrt(16/4) * 12s = 24s.
The second part of the question seems to relate to real gas density calculations, but without complete data, we cannot determine a specific answer.
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