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Answer :
Answer:
Option B. 44 is the correct answer
Step-by-step explanation:
Let l be the number of large pizzas and s be the number of small pizzas
Then according to the given statement the equations will be:
[tex]l+s = 100\ \ \ Eqn\ 1\\11l+7.5s = 848\ \ \ Eqn\ 2[/tex]
From equation 1
[tex]l = 100-s[/tex]
Putting in equation 2
[tex]11(100-s)+7.5s = 848\\1100-11s+7.5s = 848\\-3.5s+1100 = 848\\-3.5s = 848-1100\\-3.5s = -252\\\frac{-3.5s}{-3.5} = \frac{-252}{-3.5}\\s = 72[/tex]
Putting s=72 in equation 1
[tex]l+72 = 100\\l = 100-72\\l = 28[/tex]
How many more small pizzas means we have to find s-l
So,
s-l = 72-28 = 44
Hence,
Option B. 44 is the correct answer
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Final answer:
Joe sold 44 more small pizzas than large pizzas during that 6-hour period.
Explanation:
To find the number of small pizzas and large pizzas sold, we can solve a system of equations. Let x be the number of small pizzas and y be the number of large pizzas. We can set up the following equations:
x + y = 100
7.50x + 11.00y = 848
Using substitution or elimination method, we can solve for x and y. Solving this system of equations, we find that x = 44 and y = 56. Therefore, Joe sold 44 more small pizzas than large pizzas during that 6-hour period.
