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Answer :
The value of Kp for the equilibrium between water vapor and hydrogen gas at 1200 K is 10.5 torr.
The equation for the equilibrium between water vapor and hydrogen gas at 1200 K is:
H2(g) + H2O(g) ⇌ 2H2O(g)
The equilibrium constant expression for this reaction is:
Kp = (P(H2O)²) / P(H2)
where P(H2O) is the partial pressure of water vapor, P(H2) is the partial pressure of hydrogen gas, and Kp is the equilibrium constant in terms of partial pressures.
Given that the equilibrium partial pressure of water vapor is 15.0 torr and the total pressure at equilibrium is 36.3 torr, we can calculate the partial pressure of hydrogen gas as:
P(H2) = total pressure - P(H2O)
P(H2) = 36.3 torr - 15.0 torr
P(H2) = 21.3 torr
Now we can substitute the values of P(H2O) and P(H2) into the expression for Kp:
Kp = (P(H2O)²) / P(H2)
Kp = (15.0 torr)² / 21.3 torr
Kp = 10.5 torr
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