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A 1 kg model is launched vertically and reaches a height of 14.17 m. What is the initial speed of the model?
a) 4.2 ms
b) 14.17 ms
c) 19.6 ms
d) 98.1 ms

Answer :

Final answer:

To find the initial speed of a 1 kg model launched vertically that reaches a height of 14.17 m, we use the kinematics equation for motion under gravity. Solving this, we find that the initial velocity is approximately 16.7 m/s, which does not match any of the provided answer choices, indicating a possible error in the options given.

Explanation:

To determine the initial speed of the model that reaches a height of 14.17 m, we can use the principles of physics, specifically the conservation of energy or the kinematics equations for uniformly accelerated motion. According to the kinematics equations, when the model reaches its highest point, its velocity becomes zero, and all the initial kinetic energy has been converted to gravitational potential energy.

Using the equation v2 = u2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (approximately -9.81 m/s2 on Earth), and s is the displacement (height reached), we can solve for the initial velocity u. Plugging in the values gives us 0 = u2 - 2(9.81 m/s2)(14.17 m).

Solving this equation for u, we find that the initial speed u is approximately 16.7 m/s. This is not an exact match for any of the options provided, so it seems there may be a mistake in the question or the answer choices.

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