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A 24 kg crate, initially at rest on a horizontal floor, requires a 124 N horizontal force to just set it in motion. Find the coefficient of static friction between the floor and the crate.

Answer :

Final answer:

The coefficient of static friction between the floor and the crate is 0.527.

Explanation:

To find the coefficient of static friction between the floor and the crate, we can use the equation:

Frictional force = coefficient of static friction * normal force

Given that the crate requires a 124N horizontal force to just set it in motion, we can assume that the force of static friction is equal to 124N. The normal force can be calculated by multiplying the mass of the crate by the acceleration due to gravity (9.8m/s^2).

So, the normal force is 24kg * 9.8m/s^2 = 235.2N. Plugging these values into the equation, we get:

124N = coefficient of static friction * 235.2N

Solving for the coefficient of static friction:

coefficient of static friction

= 124N / 235.2N

= 0.527

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