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Answer :
It takes 669.44 J of heat to warm 16.0 g of pure water from 90.0°C to 100.0°C.
To calculate the amount of heat required to warm 16.0 g of pure water from 90.0°C to 100.0°C, we can use the formula Q = mxCxΔT, where Q is the amount of heat, m is the mass of the substance, C is the specific heat of the substance, and ΔT is the change in temperature.
Plugging in the values we have:
Q = 16.0 g x 4.184 J/g-°C x (100.0°C - 90.0°C)
Q = 16.0 g x 4.184 J/g-°C x 10.0°C
Q = 669.44 J
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