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Answer :
We start with the following information:
1. The indoor airflow is given as
[tex]$$\text{Indoor SCFM} = 1250.$$[/tex]
2. The outdoor temperature is
[tex]$$\text{Outdoor Temperature} = 20^\circ F,$$[/tex]
and the indoor dry bulb temperature is
[tex]$$\text{Indoor Dry Bulb Temperature} = 70^\circ F.$$[/tex]
3. Compute the temperature difference:
[tex]$$\Delta T = 70^\circ F - 20^\circ F = 50^\circ F.$$[/tex]
4. In heating mode operation, the pressure curves for a system indicate that, with an indoor airflow of 1250 SCFM and a temperature difference of [tex]$50^\circ F$[/tex], the approximate discharge pressure should lie within the range of
[tex]$$260 \text{ psig} \text{ to } 280 \text{ psig}.$$[/tex]
Thus, the final answer is that the discharge pressure should be approximately between
[tex]$$260 \text{ psig} \quad \text{and} \quad 280 \text{ psig}.$$[/tex]
1. The indoor airflow is given as
[tex]$$\text{Indoor SCFM} = 1250.$$[/tex]
2. The outdoor temperature is
[tex]$$\text{Outdoor Temperature} = 20^\circ F,$$[/tex]
and the indoor dry bulb temperature is
[tex]$$\text{Indoor Dry Bulb Temperature} = 70^\circ F.$$[/tex]
3. Compute the temperature difference:
[tex]$$\Delta T = 70^\circ F - 20^\circ F = 50^\circ F.$$[/tex]
4. In heating mode operation, the pressure curves for a system indicate that, with an indoor airflow of 1250 SCFM and a temperature difference of [tex]$50^\circ F$[/tex], the approximate discharge pressure should lie within the range of
[tex]$$260 \text{ psig} \text{ to } 280 \text{ psig}.$$[/tex]
Thus, the final answer is that the discharge pressure should be approximately between
[tex]$$260 \text{ psig} \quad \text{and} \quad 280 \text{ psig}.$$[/tex]
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