For a buck-boost converter operated at a switching frequency of 10 kHz, compute the output voltage and output power if:

- Load resistance is 3 ohms
- Input voltage is 13.6 V
- Duty cycles are 0.3, 0.5, and 0.9

For a buck converter with an ON time of 12 µs, where:

- Battery voltage is 14.2 V
- Required output voltage is 6.3 V

Find:

a) Switching frequency
b) OFF time

Question

High School

We appreciate your visit to For a buck boost converter operated at a switching frequency of 10 kHz compute the output voltage and output power if Load resistance is 3. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Answer :

Qwtiger Qwtiger · Answer 1 · 2023-09-02T23:38:52-04:00

a) The switching frequency of the buck-boost converter is 10 kHz.

b) The OFF time of the buck converter with an ON time of 12 µs and a required output voltage of 6.3 V is 88 µs.

a) To compute the switching frequency for the buck-boost converter operated at 10 kHz, we use the formula:

Switching frequency = 1 / switching period

Given that the switching frequency is 10 kHz, we can calculate the switching period as:

Switching period = 1 / (10 kHz) = 1 / (10,000 Hz) = 100 µs

Therefore, the switching frequency of the buck-boost converter is 10 kHz.

b) For the buck converter with an ON time of 12 µs and a required output voltage of 6.3 V, we can find the OFF time using the formula:

OFF time = Switching period - ON time

Given that the battery voltage is 14.2 V and the required output voltage is 6.3 V, we can calculate the OFF time as:

OFF time = Switching period - ON time = 100 µs - 12 µs = 88 µs

Therefore, the OFF time of the buck converter is 88 µs.

Learn more about switching frequencies at

https://brainly.com/question/33462878

#SPJ4