Answer :

To compare the 1's in each number, let's first consider their place values in both numbers:

1. In the number 124, the 1 is in the hundreds place, which gives it a place value of 100.

2. In the number 412, the 1 is in the tens place, resulting in a place value of 10.

Now we want to determine how many times the value of 1 in 412 is less than the value of 1 in 124.

To do this, we divide the larger place value (100) by the smaller place value (10):

[tex]\[
\text{Times less} = \frac{100}{10} = 10
\][/tex]

Therefore, the 1 in 412 is 10 times less than the 1 in 124.

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Rewritten by : Barada