High School

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Multiply the following polynomials:

[tex]
\[
\begin{array}{r}
x^2+4x+2 \\
\times \quad 2x^2+3x-4 \\
\hline
\end{array}
\]
[/tex]

Choose the correct answer:

A. [tex]\(3x^2+7x-2\)[/tex]

B. [tex]\(2x^4+11x^3+12x^2-10x-8\)[/tex]

C. [tex]\(2x^4+12x^2-8\)[/tex]

D. [tex]\(2x^4+23x^2-10x-8\)[/tex]

Answer :

To multiply the polynomials [tex]\( x^2 + 4x + 2 \)[/tex] and [tex]\( 2x^2 + 3x - 4 \)[/tex], we'll use the distributive property, multiplying each term in the first polynomial by each term in the second polynomial, and then combining like terms.

Here's the step-by-step procedure:

1. Multiply each term in [tex]\( x^2 + 4x + 2 \)[/tex] by each term in [tex]\( 2x^2 + 3x - 4 \)[/tex]:

- [tex]\( x^2 \)[/tex] times each term in the second polynomial:
- [tex]\( x^2 \cdot 2x^2 = 2x^4 \)[/tex]
- [tex]\( x^2 \cdot 3x = 3x^3 \)[/tex]
- [tex]\( x^2 \cdot (-4) = -4x^2 \)[/tex]

- [tex]\( 4x \)[/tex] times each term in the second polynomial:
- [tex]\( 4x \cdot 2x^2 = 8x^3 \)[/tex]
- [tex]\( 4x \cdot 3x = 12x^2 \)[/tex]
- [tex]\( 4x \cdot (-4) = -16x \)[/tex]

- [tex]\( 2 \)[/tex] times each term in the second polynomial:
- [tex]\( 2 \cdot 2x^2 = 4x^2 \)[/tex]
- [tex]\( 2 \cdot 3x = 6x \)[/tex]
- [tex]\( 2 \cdot (-4) = -8 \)[/tex]

2. Combine like terms:

- Combine the [tex]\( x^4 \)[/tex] terms: [tex]\( 2x^4 \)[/tex]
- Combine the [tex]\( x^3 \)[/tex] terms: [tex]\( 3x^3 + 8x^3 = 11x^3 \)[/tex]
- Combine the [tex]\( x^2 \)[/tex] terms: [tex]\(-4x^2 + 12x^2 + 4x^2 = 12x^2\)[/tex]
- Combine the [tex]\( x \)[/tex] terms: [tex]\(-16x + 6x = -10x\)[/tex]
- Combine the constant terms: [tex]\(-8\)[/tex]

3. Final polynomial expression:

[tex]\[
2x^4 + 11x^3 + 12x^2 - 10x - 8
\][/tex]

Therefore, the correct answer is B. [tex]\( 2x^4 + 11x^3 + 12x^2 - 10x - 8 \)[/tex].

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